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In fig ps/sq pt/tr

WebGiven: PS = PR, ∠TPS = ∠QPRTo Prove: PT = PQProof: In ∆PSR,∵ PS = PR Given∴ ∠PSR = ∠PRS ...(1) Angles opposite to equal sides of a triangle are equal⇒ ∠TPS + ∠PTS = ∠QPR + ∠PQR An exterior angle of a triangle is equal to the sum of its two interior opposite angles⇒ ∠PTS = ∠PQR Using (1)⇒ ∠PTQ = ∠PQT ∴ PT = PQ Sides opposite to equal angles of a ... WebIn the Given Figure, S and T Are Points on the Sides Pq and Pr Respectively of ∆Pqr Such that Pt = 2 Cm, Tr = 4 Cm and St is Parallel to Qr. Find the Ratio of the Areas of ∆Pst and ∆Pqr. - Mathematics. Advertisement Remove all ads. Advertisement Remove all ads. Sum.

NCERT Exemplar Class 10 Maths Solutions Chapter 6 - BYJU

WebAug 14, 2024 · In a triangle, if the square on one side is equal to the sum of the squares on the other two sides, prove that the angle opposite to the first side is a right angle. Use the above theorem to find the measure of ∠PKR in Fig. 7.51. WebIn the figure shown below , if P S SQ = P T T R and ∠ PST= ∠ PRQ, then Δ PQR is a/an triangle. Q. In below shown figure, P S SQ = P T T R and ∠ PST= ∠ PRQ. Then Δ PQR is an isosceles Triangle. Q. In the given figure, P S SQ = P T T R and ∠ PST= ∠ PRQ, then Δ PQR is _______triangle. Q. bishop fintan monahan twitter https://srsproductions.net

In the given fig., PS /SQ= PT/TR and ∠PST = ∠PRQ. Prove …

WebJan 26, 2024 · If PS=3, SQ=6, QR=5, PT=x and TR=y then the two pair of values of x and y such that line ST side QR will be (1, 2) & (2, 4). Step-by-step explanation: It is given that, ST // QR PS = 3 SQ = 6 QR = 5 PT = x TR = y WebApr 27, 2024 · In Fig., S and T are points on the sides PQ and PR respectively of A PQR such that PT = 2 cm, TR = 4 cm and ST is parallel to QR. Find the ratio of the areas of PST and PQR. triangles class-10 1 Answer +1 vote answered Apr 27, 2024 by Amishi (30.3k points) selected Apr 28, 2024 by Saadah Best answer Given ST QR, TR = 4 cm and PT = 2 cm. So, WebJul 7, 2024 · In the given figure,∠PQR = ∠PST = 90°, PQ = 5 cm and PS = 2 cm. (i) Prove that PQR ∼ APST. (ii) Find Area of PQR : Area of quadrilateral SRQT - Sarthaks eConnect Largest Online Education Community In the given figure,∠PQR = ∠PST = 90°, PQ = 5 cm and PS = 2 cm. (i) Prove that PQR ∼ APST. (ii) Find Area of PQR : Area of quadrilateral SRQT dark house 2014 full movie

Example 3 - PS/SQ = PT/TR and PST = PRQ. Prove that

Category:In figure, if ∠1 =∠2 and ΔNSQ = ΔMTR, then prove that ΔPTS ~ …

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In fig ps/sq pt/tr

In the given figure, PS / SQ = PT / TR and ∠ PST =∠ PRQ

WebFeb 8, 2024 · In the given figure, PS = 4 cm, SQ = 1 cm, PT = 6 cm and TR = 1.5 cm. Now, we have ..... (1) Hence, in Δ PQR, line ST divides the two sides of Δ PQR, PQ and PR in the … WebIn the given fig, ST QR, PS = 2 cm and SQ = 3 cm. What is the ratio of the area of ∆PQR to the area of ∆PST? from Mathematics Triangles Class 10 CBSE Triangles Advertisement …

In fig ps/sq pt/tr

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WebJul 4, 2024 · In the given figure, ST parallal to QR. If PS = 4 cm SQ = 6 cm and PT = 2.5 cm. then find TR. See answer Advertisement Brainly User PS = 4cm SQ = 6cm PT = 2.5cm TR = ? By B.P.T Theorem we know that, Here, TR = 2.5 x 6 / 4 = 15/4 = 3.7 TR = 3.7cm Advertisement New questions in Math A box contains 6 pens 2 of which are defective WebIn fig., PS = 2, SQ = 6, QR = 5, PT = x and TR = y. Then find the pair of value of x and y such that ST side QR. - Geometry. In fig., PS = 2, SQ = 6, QR = 5, PT = x and TR = y. Then find …

Web>> In fig., PQRS is square and SRT is an eq Question : In Fig. 6.16. PS/SQ = PT/TR and Z PST = PRQ Prove that POR is an isosceles triangle. Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions Prove that the median to the base of an isosceles triangle is perpendicular to the base. Medium View solution > WebFeb 25, 2024 · In fig., PS = 2, SQ = 6, QR = 5, PT = x and TR = y. Then find the pair of value of x and y such that ST II side QR.

WebSolution The correct option is A an Isosceles It is given that P S SQ = P T T R By converse of Basic Proportionality Theorem (BPT), ST QR ∴, ∠PST=∠PQR .......... (Corresponding … WebJul 30, 2024 · In Fig. PS/SQ = PT/TR and ∠ PST = ∠ PRQ. Prove that PQR is an isosceles triangle. Triangles 10th - YouTube Class-10 Maths Chapter-6, TrianglesExample No- 3In …

WebSimilarly, you may note that in the two quadrilaterals (a square and a rhombus) of Fig. 6, corresponding sides are in the same ratio, but their corresponding angles are not equal. Again, the two polygons (quadrilaterals) are not similar. TRIANGLES 123. 6 Similarity of Triangles ... In Fig. 6, PS SQ = PT TR. and ∠ PST = ∠ PRQ. Prove that PQR ...

Web`(ps)/(sq) = (pt)/(tr)` ⇒ ST QR By converse of basic proportionality theorem, If a line is drawn parallel to one side of a triangle to intersect the other sides in distinct points, the other two sides are divided in the same ratio. bishop fintan gavin crokmassWebIn the given figure, PQR is a triangle in which PQ = PR. A circle is drawn which passes through Q and touches PR at S and intersects PQ at T. If S is the mid-point of PR and PT = 4.5 cm, then length of PQ is Q. In a triangle PQR, ST is parallel to QR Show that RT (PQ + PS) = SQ (PR + PT) Q. bishop fintans office corkWebFeb 25, 2024 · Solution For In fig., PS=2,SQ=6,QR=5,PT=x and TR= y. Then find the pair of value of x and y such that ST II side QR. The world’s only live instant tutoring platform. About Us Become a Tutor. Filo instant Ask button for chrome browser. Now connect to a tutor anywhere from the web ... bishop finniganWebMar 29, 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo. bishop fintan monahanWeb>> In fig., PQRS is square and SRT is an eq Question : In Fig. 6.16. PS/SQ = PT/TR and Z PST = PRQ Prove that POR is an isosceles triangle. Solution Verified by Toppr Was this answer … dark house color ideasWebBucharest botanical garden - Nepali translation, definition, meaning, synonyms, pronunciation, transcription, antonyms, examples. English - Nepali Translator. dark house 2014 filmWebFind the area of the trapezium PQRS with height PQ given in Fig. 12.3 Solution: Given, PQRS is a trapezium with height PQ. We have to find the area of trapezium PQRS. Draw RT perpendicular to PS Now, ST = PS - PT = 12 - 7 ST = 5 m Also, PT = RQ Area of trapezium PQRS = area of triangle STR + area of rectangle PQRT Considering triangle STR, bishop financial partners